7(1+4x)=13(2x-3)

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Solution for 7(1+4x)=13(2x-3) equation: 



7(1+4x)=13(2x-3)

We move all terms to the left:

7(1+4x)-(13(2x-3))=0

We add all the numbers together, and all the variables

7(4x+1)-(13(2x-3))=0

We multiply parentheses

28x-(13(2x-3))+7=0



We calculate terms in parentheses: -(13(2x-3)), so:

13(2x-3)

We multiply parentheses

26x-39

Back to the equation:

-(26x-39)



We get rid of parentheses

28x-26x+39+7=0

We add all the numbers together, and all the variables

2x+46=0

We move all terms containing x to the left, all other terms to the right

2x=-46

x=-46/2

x=-23

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