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X(3X+4)=180
We move all terms to the left:
X(3X+4)-(180)=0
We multiply parentheses
3X^2+4X-180=0
a = 3; b = 4; c = -180;
Δ = b2-4ac
Δ = 42-4·3·(-180)
Δ = 2176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2176}=\sqrt{64*34}=\sqrt{64}*\sqrt{34}=8\sqrt{34}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8\sqrt{34}}{2*3}=\frac{-4-8\sqrt{34}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8\sqrt{34}}{2*3}=\frac{-4+8\sqrt{34}}{6} $
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