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x-1/5(8-x)=x+3(4-x)-x
We move all terms to the left:
x-1/5(8-x)-(x+3(4-x)-x)=0
Domain of the equation: 5(8-x)!=0We add all the numbers together, and all the variables
x∈R
x-1/5(-1x+8)-(x+3(-1x+4)-x)=0
We multiply all the terms by the denominator
x*5(-1x+8)-((x+3(-1x+4)-x))*5(-1x+8)-1=0
We calculate terms in parentheses: -((x+3(-1x+4)-x))*5(-1x+8), so:We add all the numbers together, and all the variables
(x+3(-1x+4)-x))*5(-1x+8
We add all the numbers together, and all the variables
-1x+(x+3(-1x+4)-x))*5(+8
Back to the equation:
-(-1x+(x+3(-1x+4)-x))*5(+8)
x*5(-1x+8)-(-1x+(x+3(-1x+4)-x))*58-1=0
Wy multiply elements
5x^2(--(-1x+(x+3(-1x+4)-x))*58-1=0
We use the square of the difference formula
5x^2(+(-1x+(x+3(-1x+4)-x))*58-1=0
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