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X(2X+7)=555
We move all terms to the left:
X(2X+7)-(555)=0
We multiply parentheses
2X^2+7X-555=0
a = 2; b = 7; c = -555;
Δ = b2-4ac
Δ = 72-4·2·(-555)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-67}{2*2}=\frac{-74}{4} =-18+1/2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+67}{2*2}=\frac{60}{4} =15 $
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