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3(x-1)-2=x-(2x+3)
We move all terms to the left:
3(x-1)-2-(x-(2x+3))=0
We multiply parentheses
3x-(x-(2x+3))-3-2=0
We calculate terms in parentheses: -(x-(2x+3)), so:We add all the numbers together, and all the variables
x-(2x+3)
We get rid of parentheses
x-2x-3
We add all the numbers together, and all the variables
-1x-3
Back to the equation:
-(-1x-3)
3x-(-1x-3)-5=0
We get rid of parentheses
3x+1x+3-5=0
We add all the numbers together, and all the variables
4x-2=0
We move all terms containing x to the left, all other terms to the right
4x=2
x=2/4
x=1/2
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