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X(2X+6)=71
We move all terms to the left:
X(2X+6)-(71)=0
We multiply parentheses
2X^2+6X-71=0
a = 2; b = 6; c = -71;
Δ = b2-4ac
Δ = 62-4·2·(-71)
Δ = 604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{604}=\sqrt{4*151}=\sqrt{4}*\sqrt{151}=2\sqrt{151}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{151}}{2*2}=\frac{-6-2\sqrt{151}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{151}}{2*2}=\frac{-6+2\sqrt{151}}{4} $
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