10(z+3)-5(z-1)=2(z-2)+2(z-2)

Solution for 10(z+3)-5(z-1)=2(z-2)+2(z-2) equation:

10(z+3)-5(z-1)=2(z-2)+2(z-2)

We move all terms to the left:

10(z+3)-5(z-1)-(2(z-2)+2(z-2))=0

We multiply parentheses

10z-5z-(2(z-2)+2(z-2))+30+5=0


We calculate terms in parentheses: -(2(z-2)+2(z-2)), so:

2(z-2)+2(z-2)

We multiply parentheses

2z+2z-4-4

We add all the numbers together, and all the variables

4z-8

Back to the equation:

-(4z-8)


We add all the numbers together, and all the variables

5z-(4z-8)+35=0

We get rid of parentheses

5z-4z+8+35=0

We add all the numbers together, and all the variables

z+43=0

We move all terms containing z to the left, all other terms to the right

z=-43