X(2X+-4)=160

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Solution for X(2X+-4)=160 equation:


Simplifying
X(2X + -4) = 160

Reorder the terms:
X(-4 + 2X) = 160
(-4 * X + 2X * X) = 160
(-4X + 2X2) = 160

Solving
-4X + 2X2 = 160

Solving for variable 'X'.

Reorder the terms:
-160 + -4X + 2X2 = 160 + -160

Combine like terms: 160 + -160 = 0
-160 + -4X + 2X2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-80 + -2X + X2) = 0

Factor a trinomial.
2((-8 + -1X)(10 + -1X)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-8 + -1X)' equal to zero and attempt to solve: Simplifying -8 + -1X = 0 Solving -8 + -1X = 0 Move all terms containing X to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1X = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1X = 0 + 8 -1X = 0 + 8 Combine like terms: 0 + 8 = 8 -1X = 8 Divide each side by '-1'. X = -8 Simplifying X = -8

Subproblem 2

Set the factor '(10 + -1X)' equal to zero and attempt to solve: Simplifying 10 + -1X = 0 Solving 10 + -1X = 0 Move all terms containing X to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1X = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1X = 0 + -10 -1X = 0 + -10 Combine like terms: 0 + -10 = -10 -1X = -10 Divide each side by '-1'. X = 10 Simplifying X = 10

Solution

X = {-8, 10}

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