X(2)+9x+1=17

Solution for X(2)+9x+1=17 equation:

X(2)+9X+1=17

We move all terms to the left:

X(2)+9X+1-(17)=0

We add all the numbers together, and all the variables

X^2+9X-16=0

a = 1; b = 9; c = -16;
Δ = b2-4ac
Δ = 92-4·1·(-16)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{145}}{2*1}=\frac{-9-\sqrt{145}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{145}}{2*1}=\frac{-9+\sqrt{145}}{2}
$