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(2a-3/a-3)-2=12/a+3
We move all terms to the left:
(2a-3/a-3)-2-(12/a+3)=0
Domain of the equation: a-3)!=0
a∈R
Domain of the equation: a+3)!=0We get rid of parentheses
a∈R
2a-3/a-12/a-3-3-2=0
We multiply all the terms by the denominator
2a*a-3*a-3*a-2*a-3-12=0
We add all the numbers together, and all the variables
-8a+2a*a-15=0
Wy multiply elements
2a^2-8a-15=0
a = 2; b = -8; c = -15;
Δ = b2-4ac
Δ = -82-4·2·(-15)
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{46}}{2*2}=\frac{8-2\sqrt{46}}{4} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{46}}{2*2}=\frac{8+2\sqrt{46}}{4} $
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