X(1+4x)=4(x-1)(x+1)+x

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Solution for X(1+4x)=4(x-1)(x+1)+x equation: 



X(1+4X)=4(X-1)(X+1)+X

We move all terms to the left:

X(1+4X)-(4(X-1)(X+1)+X)=0

We add all the numbers together, and all the variables

X(4X+1)-(4(X-1)(X+1)+X)=0

We use the square of the difference formula

X^2+X(4X+1)+1=0

We multiply parentheses

X^2+4X^2+X+1=0

We add all the numbers together, and all the variables

5X^2+X+1=0

a = 5; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·5·1
Δ = -19
Delta is less than zero, so there is no solution for the equation

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