27=3(y-3)+6y

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Solution for 27=3(y-3)+6y equation: 



27=3(y-3)+6y

We move all terms to the left:

27-(3(y-3)+6y)=0



We calculate terms in parentheses: -(3(y-3)+6y), so:

3(y-3)+6y

We add all the numbers together, and all the variables

6y+3(y-3)

We multiply parentheses

6y+3y-9

We add all the numbers together, and all the variables

9y-9

Back to the equation:

-(9y-9)



We get rid of parentheses

-9y+9+27=0

We add all the numbers together, and all the variables

-9y+36=0

We move all terms containing y to the left, all other terms to the right

-9y=-36

y=-36/-9

y=+4

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