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X(.05X+1.6)=16
We move all terms to the left:
X(.05X+1.6)-(16)=0
We multiply parentheses
X^2+1.6X-16=0
a = 1; b = 1.6; c = -16;
Δ = b2-4ac
Δ = 1.62-4·1·(-16)
Δ = 66.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{66.56}}{2*1}=\frac{-1.6-\sqrt{66.56}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{66.56}}{2*1}=\frac{-1.6+\sqrt{66.56}}{2} $
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