8x+3(x-2)=5(x+1)-4

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Solution for 8x+3(x-2)=5(x+1)-4 equation:



8x+3(x-2)=5(x+1)-4
We move all terms to the left:
8x+3(x-2)-(5(x+1)-4)=0
We multiply parentheses
8x+3x-(5(x+1)-4)-6=0
We calculate terms in parentheses: -(5(x+1)-4), so:
5(x+1)-4
We multiply parentheses
5x+5-4
We add all the numbers together, and all the variables
5x+1
Back to the equation:
-(5x+1)
We add all the numbers together, and all the variables
11x-(5x+1)-6=0
We get rid of parentheses
11x-5x-1-6=0
We add all the numbers together, and all the variables
6x-7=0
We move all terms containing x to the left, all other terms to the right
6x=7
x=7/6
x=1+1/6

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