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X^2+6X-1080=0
a = 1; b = 6; c = -1080;
Δ = b2-4ac
Δ = 62-4·1·(-1080)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-66}{2*1}=\frac{-72}{2} =-36 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+66}{2*1}=\frac{60}{2} =30 $
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