2(2m)+4(4m+2m)=108

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Solution for 2(2m)+4(4m+2m)=108 equation: 



2(2m)+4(4m+2m)=108

We move all terms to the left:

2(2m)+4(4m+2m)-(108)=0

We add all the numbers together, and all the variables

22m+4(+6m)-108=0

We multiply parentheses

22m+24m-108=0

We add all the numbers together, and all the variables

46m-108=0

We move all terms containing m to the left, all other terms to the right

46m=108

m=108/46

m=2+8/23

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