W+w*w+3+w+3=54

Solution for W+w*w+3+w+3=54 equation:

+W*W+3+W+3=54

We move all terms to the left:

+W*W+3+W+3-(54)=0

We add all the numbers together, and all the variables

W+W*W-48=0

Wy multiply elements

W^2+W-48=0

a = 1; b = 1; c = -48;
Δ = b2-4ac
Δ = 12-4·1·(-48)
Δ = 193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{193}}{2*1}=\frac{-1-\sqrt{193}}{2}
$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{193}}{2*1}=\frac{-1+\sqrt{193}}{2}
$