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3x-5=2(x-10)
We move all terms to the left:
3x-5-(2(x-10))=0
We calculate terms in parentheses: -(2(x-10)), so:We get rid of parentheses
2(x-10)
We multiply parentheses
2x-20
Back to the equation:
-(2x-20)
3x-2x+20-5=0
We add all the numbers together, and all the variables
x+15=0
We move all terms containing x to the left, all other terms to the right
x=-15
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