T=n(n-3)/2n=10

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Solution for T=n(n-3)/2n=10 equation: 



=T(T-3)/2T=10

We move all terms to the left:

-(T(T-3)/2T)=0



Domain of the equation: 2T)!=0

T!=0/1

T!=0

T∈R



We multiply all the terms by the denominator


-(T(T-3)=0



We calculate terms in parentheses: -(T(T-3), so:

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