7x+8=(x+12)+(3x+20)

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Solution for 7x+8=(x+12)+(3x+20) equation: 



7x+8=(x+12)+(3x+20)

We move all terms to the left:

7x+8-((x+12)+(3x+20))=0



We calculate terms in parentheses: -((x+12)+(3x+20)), so:

(x+12)+(3x+20)

We get rid of parentheses

x+3x+12+20

We add all the numbers together, and all the variables

4x+32

Back to the equation:

-(4x+32)



We get rid of parentheses

7x-4x-32+8=0

We add all the numbers together, and all the variables

3x-24=0

We move all terms containing x to the left, all other terms to the right

3x=24

x=24/3

x=8

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