S=2(3.14)+3x(2x+5)

Solution for S=2(3.14)+3x(2x+5) equation:

=2(3.14)+3S(2S+5)

We move all terms to the left:

-(2(3.14)+3S(2S+5))=0


We calculate terms in parentheses: -(2(3.14)+3S(2S+5)), so:

2(3.14)+3S(2S+5)

determiningTheFunctionDomain
3S(2S+5)+2(3.14)

We add all the numbers together, and all the variables

3S(2S+5)+6.28

We multiply parentheses

6S^2+15S+6.28

Back to the equation:

-(6S^2+15S+6.28)


We get rid of parentheses

-6S^2-15S-6.28=0

a = -6; b = -15; c = -6.28;
Δ = b2-4ac
Δ = -152-4·(-6)·(-6.28)
Δ = 74.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$S_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$S_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$S_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{74.28}}{2*-6}=\frac{15-\sqrt{74.28}}{-12}
$
$S_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{74.28}}{2*-6}=\frac{15+\sqrt{74.28}}{-12}
$