1/5k-(k+1/2)=1/10(k+5)

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Solution for 1/5k-(k+1/2)=1/10(k+5) equation: 



1/5k-(k+1/2)=1/10(k+5)

We move all terms to the left:

1/5k-(k+1/2)-(1/10(k+5))=0



Domain of the equation: 5k!=0

k!=0/5

k!=0

k∈R





Domain of the equation: 10(k+5))!=0

k∈R



We add all the numbers together, and all the variables

1/5k-(+k+1/2)-(1/10(k+5))=0

We get rid of parentheses

1/5k-k-(1/10(k+5))-1/2=0

We calculate fractions


(20kk/(100k^2k+(-(1*5k*2)/(100k^2k+(-50k^2)/(100k^2k-k=0

We can not solve this equation

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