S(x+3)=5(2x+1)+4x

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Solution for S(x+3)=5(2x+1)+4x equation:



(S+3)=5(2S+1)+4S
We move all terms to the left:
(S+3)-(5(2S+1)+4S)=0
We get rid of parentheses
S-(5(2S+1)+4S)+3=0
We calculate terms in parentheses: -(5(2S+1)+4S), so:
5(2S+1)+4S
We add all the numbers together, and all the variables
4S+5(2S+1)
We multiply parentheses
4S+10S+5
We add all the numbers together, and all the variables
14S+5
Back to the equation:
-(14S+5)
We get rid of parentheses
S-14S-5+3=0
We add all the numbers together, and all the variables
-13S-2=0
We move all terms containing S to the left, all other terms to the right
-13S=2
S=2/-13
S=-2/13

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