2p+8=(2+1/2p)

Solution for 2p+8=(2+1/2p) equation:

2p+8=(2+1/2p)

We move all terms to the left:

2p+8-((2+1/2p))=0


Domain of the equation: 2p))!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

2p-((1/2p+2))+8=0

We multiply all the terms by the denominator


2p*2p+8*2p+2))-((1+2))=0

We add all the numbers together, and all the variables

2p*2p+8*2p+2))-(3)=0

We add all the numbers together, and all the variables

2p*2p+8*2p=0

Wy multiply elements

4p^2+16p=0

a = 4; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·4·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*4}=\frac{-32}{8}
=-4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*4}=\frac{0}{8}
=0
$