R=(500-25x)(2+0.25x)

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Solution for R=(500-25x)(2+0.25x) equation: 



=(500-25R)(2+0.25R)

We move all terms to the left:

-((500-25R)(2+0.25R))=0

We add all the numbers together, and all the variables

-((-25R+500)(0.25R+2))=0

We multiply parentheses ..

-((+0R^2-50R+0R+1000))=0



We calculate terms in parentheses: -((+0R^2-50R+0R+1000)), so:

(+0R^2-50R+0R+1000)

We get rid of parentheses

0R^2-50R+0R+1000

We add all the numbers together, and all the variables

R^2-49R+1000

Back to the equation:

-(R^2-49R+1000)



We get rid of parentheses

-R^2+49R-1000=0

We add all the numbers together, and all the variables

-1R^2+49R-1000=0

a = -1; b = 49; c = -1000;
Δ = b2-4ac
Δ = 492-4·(-1)·(-1000)
Δ = -1599
Delta is less than zero, so there is no solution for the equation

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