2(x+2)+3=-1-3(x+1)

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Solution for 2(x+2)+3=-1-3(x+1) equation: 



2(x+2)+3=-1-3(x+1)

We move all terms to the left:

2(x+2)+3-(-1-3(x+1))=0

We multiply parentheses

2x-(-1-3(x+1))+4+3=0



We calculate terms in parentheses: -(-1-3(x+1)), so:

-1-3(x+1)

determiningTheFunctionDomain
-3(x+1)-1

We multiply parentheses

-3x-3-1

We add all the numbers together, and all the variables

-3x-4

Back to the equation:

-(-3x-4)



We add all the numbers together, and all the variables

2x-(-3x-4)+7=0

We get rid of parentheses

2x+3x+4+7=0

We add all the numbers together, and all the variables

5x+11=0

We move all terms containing x to the left, all other terms to the right

5x=-11

x=-11/5

x=-2+1/5

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