R-2(2+3r)=3r+8

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Solution for R-2(2+3r)=3r+8 equation: 



-2(2+3R)=3R+8

We move all terms to the left:

-2(2+3R)-(3R+8)=0

We add all the numbers together, and all the variables

-2(3R+2)-(3R+8)=0

We multiply parentheses

-6R-(3R+8)-4=0

We get rid of parentheses

-6R-3R-8-4=0

We add all the numbers together, and all the variables

-9R-12=0

We move all terms containing R to the left, all other terms to the right

-9R=12

R=12/-9

R=-1+1/3

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