P=x+(3x-3)+(4x-5)

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Solution for P=x+(3x-3)+(4x-5) equation: 



=P+(3P-3)+(4P-5)

We move all terms to the left:

-(P+(3P-3)+(4P-5))=0



We calculate terms in parentheses: -(P+(3P-3)+(4P-5)), so:

P+(3P-3)+(4P-5)

We get rid of parentheses

P+3P+4P-3-5

We add all the numbers together, and all the variables

8P-8

Back to the equation:

-(8P-8)



We get rid of parentheses

-8P+8=0

We move all terms containing P to the left, all other terms to the right

-8P=-8

P=-8/-8

P=1

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