112=-16t2+128t

Solution for 112=-16t2+128t equation:

112=-16t^2+128t

We move all terms to the left:

112-(-16t^2+128t)=0

We get rid of parentheses

16t^2-128t+112=0

a = 16; b = -128; c = +112;
Δ = b2-4ac
Δ = -1282-4·16·112
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-128)-96}{2*16}=\frac{32}{32}
=1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-128)+96}{2*16}=\frac{224}{32}
=7
$