n/3=(n+4)/7

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Solution for n/3=(n+4)/7 equation: 



n/3=(n+4)/7

We move all terms to the left:

n/3-((n+4)/7)=0

We calculate fractions


7n^2/()+(-((n+4)*3)/()=0



We calculate terms in parentheses: +(-((n+4)*3)/(), so:

-((n+4)*3)/(

We multiply all the terms by the denominator


-((n+4)*3)



We calculate terms in parentheses: -((n+4)*3), so:

(n+4)*3

We multiply parentheses

3n+12

Back to the equation:

-(3n+12)



We get rid of parentheses

-3n-12

Back to the equation:

+(-3n-12)



We get rid of parentheses

7n^2/()-3n-12=0

We multiply all the terms by the denominator


7n^2-3n*()-12*()=0

We add all the numbers together, and all the variables

7n^2-3n*()=0

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