P(x)=(x+2)(x+5)

Solution for P(x)=(x+2)(x+5) equation:

(P)=(P+2)(P+5)

We move all terms to the left:

(P)-((P+2)(P+5))=0

We multiply parentheses ..

-((+P^2+5P+2P+10))+P=0


We calculate terms in parentheses: -((+P^2+5P+2P+10)), so:

(+P^2+5P+2P+10)

We get rid of parentheses

P^2+5P+2P+10

We add all the numbers together, and all the variables

P^2+7P+10

Back to the equation:

-(P^2+7P+10)


We add all the numbers together, and all the variables

P-(P^2+7P+10)=0

We get rid of parentheses

-P^2+P-7P-10=0

We add all the numbers together, and all the variables

-1P^2-6P-10=0

a = -1; b = -6; c = -10;
Δ = b2-4ac
Δ = -62-4·(-1)·(-10)
Δ = -4
Delta is less than zero, so there is no solution for the equation