(j+8)(j-8)=j

Solution for (j+8)(j-8)=j equation:

(j+8)(j-8)=j

We move all terms to the left:

(j+8)(j-8)-(j)=0

We add all the numbers together, and all the variables

-1j+(j+8)(j-8)=0

We use the square of the difference formula

j^2-1j-64=0

a = 1; b = -1; c = -64;
Δ = b2-4ac
Δ = -12-4·1·(-64)
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{257}}{2*1}=\frac{1-\sqrt{257}}{2}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{257}}{2*1}=\frac{1+\sqrt{257}}{2}
$