N1=t(N2-N3)+N3,N2

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Solution for N1=t(N2-N3)+N3,N2 equation: 



1=N(2-3)+3.2

We move all terms to the left:

1-(N(2-3)+3.2)=0

We add all the numbers together, and all the variables

-(N(-1)+3.2)+1=0



We calculate terms in parentheses: -(N(-1)+3.2), so:

N(-1)+3.2

We multiply parentheses

-1N+3.2

Back to the equation:

-(-1N+3.2)



We get rid of parentheses

1N-3.2+1=0

We add all the numbers together, and all the variables

N-2.2=0

We move all terms containing N to the left, all other terms to the right

N=2.2

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