N(t)=400(2+3t+t+2)

Solution for N(t)=400(2+3t+t+2) equation:

(N)=400(2+3N+N+2)

We move all terms to the left:

(N)-(400(2+3N+N+2))=0

We add all the numbers together, and all the variables

N-(400(4N+4))=0


We calculate terms in parentheses: -(400(4N+4)), so:

400(4N+4)

We multiply parentheses

1600N+1600

Back to the equation:

-(1600N+1600)


We get rid of parentheses

N-1600N-1600=0

We add all the numbers together, and all the variables

-1599N-1600=0

We move all terms containing N to the left, all other terms to the right

-1599N=1600

N=1600/-1599

N=-1+1/1599