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(2x+5)(6x-3)=0
We multiply parentheses ..
(+12x^2-6x+30x-15)=0
We get rid of parentheses
12x^2-6x+30x-15=0
We add all the numbers together, and all the variables
12x^2+24x-15=0
a = 12; b = 24; c = -15;
Δ = b2-4ac
Δ = 242-4·12·(-15)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-36}{2*12}=\frac{-60}{24} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+36}{2*12}=\frac{12}{24} =1/2 $
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