3(z+2z)=60+3z-4z

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Solution for 3(z+2z)=60+3z-4z equation: 



3(z+2z)=60+3z-4z

We move all terms to the left:

3(z+2z)-(60+3z-4z)=0

We add all the numbers together, and all the variables

3(+3z)-(-1z+60)=0

We multiply parentheses

9z-(-1z+60)=0

We get rid of parentheses

9z+1z-60=0

We add all the numbers together, and all the variables

10z-60=0

We move all terms containing z to the left, all other terms to the right

10z=60

z=60/10

z=6

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