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3x+1=3(2-x)
We move all terms to the left:
3x+1-(3(2-x))=0
We add all the numbers together, and all the variables
3x-(3(-1x+2))+1=0
We calculate terms in parentheses: -(3(-1x+2)), so:We get rid of parentheses
3(-1x+2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
3x+3x-6+1=0
We add all the numbers together, and all the variables
6x-5=0
We move all terms containing x to the left, all other terms to the right
6x=5
x=5/6
x=5/6
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