L=2C+11(12+2)/7+(12-2)4c

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Solution for L=2C+11(12+2)/7+(12-2)4c equation: 



=2+11(12+2)/7+(12-2)4L

We move all terms to the left:

-(2+11(12+2)/7+(12-2)4L)=0



Domain of the equation: 7+(12-2)4L)!=0

We move all terms containing L to the left, all other terms to the right

(12-2)4L)!=-7

L∈R



We add all the numbers together, and all the variables

-(2+1114/7+104L)=0

We get rid of parentheses

-104L-2-1114/7=0

We multiply all the terms by the denominator


-104L*7-1114-2*7=0

We add all the numbers together, and all the variables

-104L*7-1128=0

Wy multiply elements

-728L-1128=0

We move all terms containing L to the left, all other terms to the right

-728L=1128

L=1128/-728

L=-1+50/91

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