10(5x+2)=7(6x-4)

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Solution for 10(5x+2)=7(6x-4) equation: 



10(5x+2)=7(6x-4)

We move all terms to the left:

10(5x+2)-(7(6x-4))=0

We multiply parentheses

50x-(7(6x-4))+20=0



We calculate terms in parentheses: -(7(6x-4)), so:

7(6x-4)

We multiply parentheses

42x-28

Back to the equation:

-(42x-28)



We get rid of parentheses

50x-42x+28+20=0

We add all the numbers together, and all the variables

8x+48=0

We move all terms containing x to the left, all other terms to the right

8x=-48

x=-48/8

x=-6

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