6t+1/9t-4=2t+5/3t-4

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Solution for 6t+1/9t-4=2t+5/3t-4 equation:



6t+1/9t-4=2t+5/3t-4
We move all terms to the left:
6t+1/9t-4-(2t+5/3t-4)=0
Domain of the equation: 9t!=0
t!=0/9
t!=0
t∈R
Domain of the equation: 3t-4)!=0
t∈R
We get rid of parentheses
6t+1/9t-2t-5/3t+4-4=0
We calculate fractions
6t-2t+3t/27t^2+(-45t)/27t^2+4-4=0
We add all the numbers together, and all the variables
4t+3t/27t^2+(-45t)/27t^2=0
We multiply all the terms by the denominator
4t*27t^2+3t+(-45t)=0
We add all the numbers together, and all the variables
3t+4t*27t^2+(-45t)=0
Wy multiply elements
108t^3+3t+(-45t)=0
We get rid of parentheses
108t^3+3t-45t=0
We do not support etpression: t^3

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