I3(x+2)-10=4x-6+x

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Solution for I3(x+2)-10=4x-6+x equation: 



3(I+2)-10=4I-6+I

We move all terms to the left:

3(I+2)-10-(4I-6+I)=0

We add all the numbers together, and all the variables

3(I+2)-(5I-6)-10=0

We multiply parentheses

3I-(5I-6)+6-10=0

We get rid of parentheses

3I-5I+6+6-10=0

We add all the numbers together, and all the variables

-2I+2=0

We move all terms containing I to the left, all other terms to the right

-2I=-2

I=-2/-2

I=1

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