-6(9x-3)=3(6-18x)

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Solution for -6(9x-3)=3(6-18x) equation: 



-6(9x-3)=3(6-18x)

We move all terms to the left:

-6(9x-3)-(3(6-18x))=0

We add all the numbers together, and all the variables

-6(9x-3)-(3(-18x+6))=0

We multiply parentheses

-54x-(3(-18x+6))+18=0



We calculate terms in parentheses: -(3(-18x+6)), so:

3(-18x+6)

We multiply parentheses

-54x+18

Back to the equation:

-(-54x+18)



We get rid of parentheses

-54x+54x-18+18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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