I3(2b-1)-7=6b-10

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Solution for I3(2b-1)-7=6b-10 equation: 



3(2I-1)-7=6I-10

We move all terms to the left:

3(2I-1)-7-(6I-10)=0

We multiply parentheses

6I-(6I-10)-3-7=0

We get rid of parentheses

6I-6I+10-3-7=0

We add all the numbers together, and all the variables

=0

I=0/1

I=0

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