3(3x-1)+5=8(x+2)+3

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Solution for 3(3x-1)+5=8(x+2)+3 equation: 



3(3x-1)+5=8(x+2)+3

We move all terms to the left:

3(3x-1)+5-(8(x+2)+3)=0

We multiply parentheses

9x-(8(x+2)+3)-3+5=0



We calculate terms in parentheses: -(8(x+2)+3), so:

8(x+2)+3

We multiply parentheses

8x+16+3

We add all the numbers together, and all the variables

8x+19

Back to the equation:

-(8x+19)



We add all the numbers together, and all the variables

9x-(8x+19)+2=0

We get rid of parentheses

9x-8x-19+2=0

We add all the numbers together, and all the variables

x-17=0

We move all terms containing x to the left, all other terms to the right

x=17

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