I-7(x-4)+2x=-2(x-5)

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Solution for I-7(x-4)+2x=-2(x-5) equation: 



-7(I-4)+2I=-2(I-5)

We move all terms to the left:

-7(I-4)+2I-(-2(I-5))=0

We add all the numbers together, and all the variables

2I-7(I-4)-(-2(I-5))=0

We multiply parentheses

2I-7I-(-2(I-5))+28=0



We calculate terms in parentheses: -(-2(I-5)), so:

-2(I-5)

We multiply parentheses

-2I+10

Back to the equation:

-(-2I+10)



We add all the numbers together, and all the variables

-5I-(-2I+10)+28=0

We get rid of parentheses

-5I+2I-10+28=0

We add all the numbers together, and all the variables

-3I+18=0

We move all terms containing I to the left, all other terms to the right

-3I=-18

I=-18/-3

I=+6

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