-4(-2q+8)=-6(q-8)+12q

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Solution for -4(-2q+8)=-6(q-8)+12q equation: 



-4(-2q+8)=-6(q-8)+12q

We move all terms to the left:

-4(-2q+8)-(-6(q-8)+12q)=0

We multiply parentheses

8q-(-6(q-8)+12q)-32=0



We calculate terms in parentheses: -(-6(q-8)+12q), so:

-6(q-8)+12q

We add all the numbers together, and all the variables

12q-6(q-8)

We multiply parentheses

12q-6q+48

We add all the numbers together, and all the variables

6q+48

Back to the equation:

-(6q+48)



We get rid of parentheses

8q-6q-48-32=0

We add all the numbers together, and all the variables

2q-80=0

We move all terms containing q to the left, all other terms to the right

2q=80

q=80/2

q=40

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