H=6+50-16x2

Solution for H=6+50-16x2 equation:

=6+50-16H^2

We move all terms to the left:

-(6+50-16H^2)=0

We get rid of parentheses

16H^2-6-50=0

We add all the numbers together, and all the variables

16H^2-56=0

a = 16; b = 0; c = -56;
Δ = b2-4ac
Δ = 02-4·16·(-56)
Δ = 3584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3584}=\sqrt{256*14}=\sqrt{256}*\sqrt{14}=16\sqrt{14}$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{14}}{2*16}=\frac{0-16\sqrt{14}}{32}
=-\frac{16\sqrt{14}}{32}
=-\frac{\sqrt{14}}{2}
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{14}}{2*16}=\frac{0+16\sqrt{14}}{32}
=\frac{16\sqrt{14}}{32}
=\frac{\sqrt{14}}{2}
$