H(n)=-12+5(n-1)

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Solution for H(n)=-12+5(n-1) equation: 



(H)=-12+5(H-1)

We move all terms to the left:

(H)-(-12+5(H-1))=0



We calculate terms in parentheses: -(-12+5(H-1)), so:

-12+5(H-1)

determiningTheFunctionDomain
5(H-1)-12

We multiply parentheses

5H-5-12

We add all the numbers together, and all the variables

5H-17

Back to the equation:

-(5H-17)



We get rid of parentheses

H-5H+17=0

We add all the numbers together, and all the variables

-4H+17=0

We move all terms containing H to the left, all other terms to the right

-4H=-17

H=-17/-4

H=4+1/4

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