1/5(b+30)=7

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Solution for 1/5(b+30)=7 equation: 



1/5(b+30)=7

We move all terms to the left:

1/5(b+30)-(7)=0



Domain of the equation: 5(b+30)!=0

b∈R



We multiply all the terms by the denominator


-7*5(b+30)+1=0

Wy multiply elements

-35b(b+1=0

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