G(x)=x(x+4)+5

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Solution for G(x)=x(x+4)+5 equation: 



(G)=G(G+4)+5

We move all terms to the left:

(G)-(G(G+4)+5)=0



We calculate terms in parentheses: -(G(G+4)+5), so:

G(G+4)+5

We multiply parentheses

G^2+4G+5

Back to the equation:

-(G^2+4G+5)



We get rid of parentheses

-G^2+G-4G-5=0

We add all the numbers together, and all the variables

-1G^2-3G-5=0

a = -1; b = -3; c = -5;
Δ = b2-4ac
Δ = -32-4·(-1)·(-5)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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